A fit is explicit when a color has been explicitly bidded by a player then supported explicitly by his partner. Examples :
1![]() |
1![]() |
3![]() ![]() |
4![]() ![]() |
The opener may bid his first control 4
ou 4
if he has a slam hope.
1![]() |
1![]() |
1![]() ![]() ![]() |
3![]() |
A fit is implicit when a color has been explicitly bidded by a player, then supported implicitly by his partner.
Some examples.
1NT | 2![]() |
2NT (2 majors) | 3![]() ![]() ![]() |
3![]() |
4![]() ![]() |
or :
1NT | 2![]() |
2![]() ![]() |
3![]() ![]() |
4![]() ![]() |
or more :
1NT | 2![]() ![]() |
2![]() |
3![]() |
3![]() ![]() |
4![]() ![]() |
and
1![]() |
1![]() |
4![]() |
* With 4, singleton
, forcing game
By all theese events of implicit fit, the control bid is used both as fitting bid and as slame hope. And whatever the fit is explicit or implicit, the
controls operate perfectly. It would be possible to show many other examples, and generally the control bids overeach the level of 3NT.
Why do theese controls perfectly operate ? For a simple and single reason : The fitted color to play is always designated before the explicit or implicit
control.
But if a control is bidded before the color to play has been designated, that brings many problems, even if this control shows clearly the frame of a hand
1NT | 2![]() |
2![]() |
3![]() ![]() ![]() |
? (with fit ![]() |
If the opener has no fit no problem, he bids 3NT.
But if he has fit
he must bid
4
because he does not know if the responder
has just 9HCP or at the contrary 16-17HCP and a slam hope.
If the opener bidded an implicit control 4
or 4
after
3
when the responder has just 9HCP, the
responder would have no other bid than 4
and would have to play himself this contract. Therefore the controls are not possible.
2NT | 3![]() |
2![]() |
3![]() ![]() ![]() |
? (with fit ![]() |
The problem is exactly the same. The reponder may have as well 4-5HCP as 12-13HCP.
2NT | 3![]() |
3NT (2 maj. 4°) | ? |
There is a fit in a least one major. After 3NT from opener The responder bids his major by transfer at level 4. The opener must complete to the major of responder, because this last may have only 5HCP. The controls are not possible.
For our visitors who have not yet read the "majeure précisée", main subject of our site, the openings
1 and 2
are exactly and respectively equivalent to
classical openings 1NT and 2NT, that is to say balanced and with 15-17HCP and with 20-21HCP.
1![]() |
2![]() ![]() ![]() ![]() ![]() ![]() ![]() |
2![]() |
|
2![]() ![]() |
|
2![]() ![]() |
|
2NT (with 4![]() ![]() |
* After the answer 2 the responder closes to 4
and after answer
2
to 4
, for game. With slam hope he bids his first control
at level 4.
** The responder bids his 4cards-major by transfer, 3 for
or 3
for
. After completing by opener in the responder's major
the responder closes to game in the designated major, but he bids his first control if he has a slam hope.
The answer 2 from opener :
1![]() |
2![]() ![]() ![]() ![]() ![]() ![]() ![]() |
2![]() |
2![]() ![]() ![]() |
2![]() ![]() ![]() |
|
3![]() ![]() ![]() |
|
3![]() ![]() ![]() |
* The opener corrects to 2NT or 3NT according to his strenght. If corrected to 2NT, the responder closes to 3NT with at least 10HCP.
(If the responder has a five-cards major with 8HCP that he will show via a Stayman bidding, he has at his disposal 2 other disrinct auctions. Read if necessary
Stayman bidding with five-cards major. about this matter.)
** If fitted the opener cmpletes in five-cards major of responder. If not he completes to 3NT.
Theese economical biddings 3 et 3
are quite distinct
from mixed 4M 5m two-suited which are included in the indirect Stayman 2
.
Theese same mechanisms cannot be used due to the higher bidding level. But the economical nature of the opening
2 enables biddinngs whith same efficiency.
2![]() |
3![]() ![]() ![]() ![]() ![]() |
3![]() ![]() ![]() |
|
3![]() ![]() |
|
3SA (avec 2![]() ![]() |
* The response 3 denies 4
, because the response
3
has always priority over response 3
. With
4
the opener woukd have bidded 4
.
Therefore, after 3 the responder closes to 4
for game, but bids his
first control if he has a slam hope.
If the responder has 4 4
, he
bids 3
what requires completing to 3NT by opener.
** The responder closes to 4 for game. With slam hope he bids his first control.
2![]() |
3![]() ![]() ![]() |
3![]() ![]() |
|
3![]() ![]() ![]() |
|
3SA (avec 2![]() ![]() |
* The responder closes to 4 for game. With slam hope he bids his first control.
** The responder closes to 4
for game. With slam hope he bids his first control.
NB : After the respose 3 ou 3
, if the opener notes 2 major fits
he bids the major he has rather to play.
When there is a fit in a major, its color is always designated by the opener at level 3. That enables the respondre to bid his first control if he has a slam hope.
If the responder has 4 4
he must not
bid 3
because he could receive the response 3
from opener
if this last has 3
2
ou 3
.
This bid 3
would force him to bid and play 3NT. At the contrary if he
bids 3
the contact of 3NT will be played by opener.
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